What is the derivative of y= x/9-9/x ?

The derivative of y= x/9-9/x is 1/9+9/(x^2)

What is the first derivative of y= x/9-9/x ?

The first derivative of y= x/9-9/x is 1/9+9/(x^2)

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derivative of

y = \frac{x}{9} - \frac{9}{x}

\frac{1}{9} + \frac{9}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{9} - \frac{9}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{9}) - \frac{d}{d x} (\frac{9}{x})

\frac{d}{d x} (\frac{x}{9}) = \frac{1}{9}

\frac{d}{d x} (\frac{9}{x}) = - \frac{9}{x ^{2}}

= \frac{1}{9} - (- \frac{9}{x ^{2}})

Simplify

= \frac{1}{9} + \frac{9}{x ^{2}}

\frac{d}{d x} (3 + 3 cos (x))

\int 15 x 1 - x d x

\int \frac{1}{( x ^{2} + 6 x + 13 )} d x

\frac{d}{d x} (2^{x^{2} + 3 x + 4})

x^{3} - 3 x

What is the derivative of y= x/9-9/x ?
The derivative of y= x/9-9/x is 1/9+9/(x^2)
What is the first derivative of y= x/9-9/x ?
The first derivative of y= x/9-9/x is 1/9+9/(x^2)