What is the derivative of (x^3+2x^4) ?

The derivative of (x^3+2x^4) is 4(x^3+2x)^3(3x^2+2)

What is the first derivative of (x^3+2x^4) ?

The first derivative of (x^3+2x^4) is 4(x^3+2x)^3(3x^2+2)

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\frac{d}{d x} ((x^{3} + 2 x)^{4})

4 (x^{3} + 2 x)^{3} (3 x^{2} + 2)

Solution steps

\frac{d}{d x} ((x^{3} + 2 x)^{4})

Apply the chain rule:

4 (x^{3} + 2 x)^{3} \frac{d}{d x} (x^{3} + 2 x)

= 4 (x^{3} + 2 x)^{3} \frac{d}{d x} (x^{3} + 2 x)

\frac{d}{d x} (x^{3} + 2 x) = 3 x^{2} + 2

= 4 (x^{3} + 2 x)^{3} (3 x^{2} + 2)

f (x) = \frac{( x - 1 ) ^{2}}{( x + 2 )}

x sin (y) + y sin (x) = 6

y^{^{'}} + 5 x e^{y} = 0

\frac{\partial}{\partial x} (2 y cos (9 y^{2} x))

x \to 0 lim (x^{\frac{1}{2}})

What is the derivative of (x^3+2x^4) ?
The derivative of (x^3+2x^4) is 4(x^3+2x)^3(3x^2+2)
What is the first derivative of (x^3+2x^4) ?
The first derivative of (x^3+2x^4) is 4(x^3+2x)^3(3x^2+2)