What is implicit xsin(y)+ysin(x)=6 ?

The answer to implicit xsin(y)+ysin(x)=6 is (dy)/(dx)=(-sin(y)-ycos(x))/(xcos(y)+sin(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

implicit xsin(y)+ysin(x)=6

implicit derivative

x sin (y) + y sin (x) = 6

\frac{d y}{d x} = \frac{- sin ( y ) - y cos ( x )}{x cos ( y ) + sin ( x )}

Solution steps

x sin (y) + y sin (x) = 6

Treat

y

y (x)

Differentiate both sides:

sin (y) + x cos (y) \frac{d y}{d x} + \frac{d y}{d x} sin (x) + cos (x) y = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- sin ( y ) - y cos ( x )}{x cos ( y ) + sin ( x )}

\frac{d y}{d x} = \frac{- sin ( y ) - y cos ( x )}{x cos ( y ) + sin ( x )}

y^{^{'}} + 5 x e^{y} = 0

\frac{\partial}{\partial x} (2 y cos (9 y^{2} x))

x \to 0 lim (x^{\frac{1}{2}})

\int 2 x tan (x) d x

x \to 2 - lim (4 - x^{2})

What is implicit xsin(y)+ysin(x)=6 ?
The answer to implicit xsin(y)+ysin(x)=6 is (dy)/(dx)=(-sin(y)-ycos(x))/(xcos(y)+sin(x))