What is the integral of (-3)/x ?

The integral of (-3)/x is -3ln|x|+C

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integral of (-3)/x

\int \frac{- 3}{x} d x

- 3 ln ∣ x ∣ + C

Solution steps

\int \frac{- 3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= - 3 ln ∣ x ∣

Add a constant to the solution

= - 3 ln ∣ x ∣ + C

\int \frac{4 t - 3}{t + 1} d t

f (x) = x^{4} + 5 x^{2} - x, (1, 5)

\int \frac{4 x + 3}{x ^{2} + 4} d x

(x^{4} - x + y) d x - x d y = 0

ln (x x^{2} + 1)