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Popular >

(x^4-x+y)dx-xdy=0

Solution

(x^{4} - x + y) d x - x d y = 0

Solution

y = \frac{x ^{4}}{3} - x ln (x) + c_{1} x

Solution steps

(x^{4} - x + y) d x - x d y = 0

Solve linear ODE:

y = \frac{x ^{4}}{3} - x ln (x) + c_{1} x

y = \frac{x ^{4}}{3} - x ln (x) + c_{1} x

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\int_{1}^{2} x e^{x^{2}} d x

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Frequently Asked Questions (FAQ)

What is the solution for (x^4-x+y)dx-xdy=0 ?
The solution for (x^4-x+y)dx-xdy=0 is y=(x^4)/3-xln(x)+c_{1}x