What is the derivative of \sqrt[7]{x} ?

The derivative of \sqrt[7]{x} is 1/(7x^{6/7)}

What is the first derivative of \sqrt[7]{x} ?

The first derivative of \sqrt[7]{x} is 1/(7x^{6/7)}

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derivative of

\frac{1}{7 x ^{\frac{6}{7}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{7}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{7} x^{\frac{1}{7} - 1}

Simplify

\frac{1}{7} x^{\frac{1}{7} - 1} : \frac{1}{7 x ^{\frac{6}{7}}}

= \frac{1}{7 x ^{\frac{6}{7}}}

x \to 1 lim (2 x - 2)

y = \frac{3}{x}

\int \frac{1}{( x ^{2} + 16 ) ^{3}} d x

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What is the derivative of \sqrt[7]{x} ?
The derivative of \sqrt[7]{x} is 1/(7x^{6/7)}
What is the first derivative of \sqrt[7]{x} ?
The first derivative of \sqrt[7]{x} is 1/(7x^{6/7)}