What is the d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) ?

The d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) is -({z)/y}{({x}^2+{y}^2+{z}^2)^{3/2}}

What is the first d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) ?

The first d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) is -({z)/y}{({x}^2+{y}^2+{z}^2)^{3/2}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d y} (\frac{z}{x ^{2} + y ^{2} + z ^{2}})

- \frac{z y}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d y} (\frac{z}{x ^{2} + y ^{2} + z ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{d}{d y} (\frac{1}{x ^{2} + y ^{2} + z ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= z \frac{d}{d y} ((x^{2} + y^{2} + z^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d y} (x^{2} + y^{2} + z^{2})

= - \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \frac{d}{d y} (x^{2} + y^{2} + z^{2})

\frac{d}{d y} (x^{2} + y^{2} + z^{2}) = 2 y

= z (- \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \cdot 2 y)

Simplify

z (- \frac{1}{2 ( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} \cdot 2 y) : - \frac{z y}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

= - \frac{z y}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}}

e^{3 t^{2}}

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

\int \frac{e ^{2 x}}{e ^{2 x} + 3} d x

\frac{d}{d x} (\frac{x ^{1 - a}}{1 - a})

\frac{\partial}{\partial x} ((f (x))^{^{'}})

What is the d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) ?
The d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) is -({z)/y}{({x}^2+{y}^2+{z}^2)^{3/2}}
What is the first d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) ?
The first d/(d{y)}(({z})/(sqrt({x)^2+{y)^2+{z}^2}}) is -({z)/y}{({x}^2+{y}^2+{z}^2)^{3/2}}