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Popular >

x*y^'=sqrt(1-y^2)

Solution

x \cdot y^{^{'}} = 1 - y^{2}

Solution

y = sin (ln (x) + c_{1})

Solution steps

x \cdot y^{'} (x) = 1 - y^{2}

Solve separable ODE:

y = sin (ln (x) + c_{1})

y = sin (ln (x) + c_{1})

Popular Examples

(\partial)/(\partial y)(arctan(xsqrt(y)))

\frac{\partial}{\partial y} (arctan (x y))

derivative of (ax+by(x)/(cx+dy))

\frac{d}{d x} (\frac{a x + b y ( x )}{c x + d y})

derivative of (e^x-1/(e^x+1))

\frac{d}{d x} (\frac{e ^{x} - 1}{e ^{x} + 1})

derivative of 1/((x^4+1^3))

\frac{d}{d x} (\frac{1}{( x ^{4} + 1 ) ^{3}})

tangent of 4.9x^{1.9},\at x=1.4 tangent of

4.9 x^{1.9}, at x = 1.4

Frequently Asked Questions (FAQ)

What is the solution for x*y^'=sqrt(1-y^2) ?
The solution for x*y^'=sqrt(1-y^2) is y=sin(ln(x)+c_{1})