What is derivative of f(x)= 9/(sqrt(t)) ?

The answer to derivative of f(x)= 9/(sqrt(t)) is (dt)/(dx)=0

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derivative of f(x)= 9/(sqrt(t))

derivative of

f (x) = \frac{9}{t}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{9}{t}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{9 \frac{d t}{d x}}{2 t ^{\frac{3}{2}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d y}{d x}, 25 x^{2} - 10 x y + 4 y^{2} = 100

\int \frac{( x ^{3} )}{9 - x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (x^{e^{x}})

h (x) = \frac{( 3 x - 5 )}{1 - x ^{2}}

\frac{d}{d x} (3 x^{2})

What is derivative of f(x)= 9/(sqrt(t)) ?
The answer to derivative of f(x)= 9/(sqrt(t)) is (dt)/(dx)=0