What is the derivative of sqrt(3x^2) ?

The derivative of sqrt(3x^2) is square root of 3

What is the first derivative of sqrt(3x^2) ?

The first derivative of sqrt(3x^2) is square root of 3

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\frac{d}{d x} (3 x^{2})

3

Solution steps

\frac{d}{d x} (3 x^{2})

Apply the chain rule:

\frac{1}{2 3 x ^{2}} \frac{d}{d x} (3 x^{2})

= \frac{1}{2 3 x ^{2}} \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

= \frac{1}{2 3 x ^{2}} \cdot 6 x

Simplify

\frac{1}{2 3 x ^{2}} \cdot 6 x : 3

= 3

\frac{d}{d x} (2 x^{3} + \frac{5 x + 1}{3 x - 5} - \frac{2}{x ^{3}})

y^{^{'}} + y = 8 x e^{x}

\frac{d}{d x} (\frac{1}{12} (x + 2)^{3} + (x + 2)^{- 1})

x \to 0 lim (\frac{7 ^{x} - 9 ^{x}}{x})

g (t) = 4 t^{- \frac{1}{8}}

What is the derivative of sqrt(3x^2) ?
The derivative of sqrt(3x^2) is square root of 3
What is the first derivative of sqrt(3x^2) ?
The first derivative of sqrt(3x^2) is square root of 3