What is (\partial)/(\partial x)(sin(pi(x-6y))) ?

The answer to (\partial)/(\partial x)(sin(pi(x-6y))) is cos(pi(x-6y))pi

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(\partial)/(\partial x)(sin(pi(x-6y)))

\frac{\partial}{\partial x} (sin (π (x - 6 y)))

cos (π (x - 6 y)) π

Solution steps

\frac{\partial}{\partial x} (sin (π (x - 6 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (x - 6 y)) \frac{\partial}{\partial x} (π (x - 6 y))

= cos (π (x - 6 y)) \frac{\partial}{\partial x} (π (x - 6 y))

\frac{\partial}{\partial x} (π (x - 6 y)) = π

= cos (π (x - 6 y)) π

\int π (4 x)^{2} d x

\int \frac{x ^{2}}{9 + x ^{2}} d x

\frac{d}{d x} ((x^{2} - 4)^{\frac{1}{3}})

x = - 2, x = 1, y = 2 x^{2} + 4, y = 0

\int x^{3} cos (n x) d x

What is (\partial)/(\partial x)(sin(pi(x-6y))) ?
The answer to (\partial)/(\partial x)(sin(pi(x-6y))) is cos(pi(x-6y))pi