What is the derivative of 2ce^{2x} ?

The derivative of 2ce^{2x} is 4ce^{2x}

What is the first derivative of 2ce^{2x} ?

The first derivative of 2ce^{2x} is 4ce^{2x}

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\frac{d}{d x} (2 c e^{2 x})

4 c e^{2 x}

Solution steps

\frac{d}{d x} (2 c e^{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 c \frac{d}{d x} (e^{2 x})

Apply the chain rule:

e^{2 x} \frac{d}{d x} (2 x)

= e^{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 c e^{2 x} \cdot 2

Simplify

= 4 c e^{2 x}

\frac{d y}{d x} = \frac{( 2 x ( y - 2 ) )}{x ^{2} + 1}, y (0) = 4

t \to 0 lim (e^{- t})

y = \frac{1}{2} (e^{x} + e^{- x})

\int 2 x (x^{2} - 7)^{99} d x

\frac{\partial}{\partial y} (e^{x y z^{8}} y z^{8})

What is the derivative of 2ce^{2x} ?
The derivative of 2ce^{2x} is 4ce^{2x}
What is the first derivative of 2ce^{2x} ?
The first derivative of 2ce^{2x} is 4ce^{2x}