What is inverse oflaplace 8/(s-3) ?

The answer to inverse oflaplace 8/(s-3) is 8e^{3t}

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inverse oflaplace 8/(s-3)

inverse laplace

\frac{8}{s - 3}

8 e^{3 t}

Solution steps

L^{- 1} {\frac{8}{s - 3}}

= L^{- 1} {8 \cdot \frac{1}{s - 3}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 8 L^{- 1} {\frac{1}{s - 3}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 3}} = e^{3 t}

= 8 e^{3 t}

\frac{d}{d x} (2 sin (x) + 4 cos (x))

\int 3 t^{5} d t

\frac{d}{d x} (x^{2} cos (π x))

\frac{d}{d x} (\frac{5}{x - 3})

\int - 4 cos (x) d x

What is inverse oflaplace 8/(s-3) ?
The answer to inverse oflaplace 8/(s-3) is 8e^{3t}