What is the solution for (e^x-2xy)dx-x^2dy=0 ?

The solution for (e^x-2xy)dx-x^2dy=0 is y=(e^x)/(x^2)+(c_{1})/(x^2)

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(e^x-2xy)dx-x^2dy=0

(e^{x} - 2 x y) d x - x^{2} d y = 0

y = \frac{e ^{x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

(e^{x} - 2 x y) d x - x^{2} d y = 0

Solve linear ODE:

y = \frac{e ^{x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{e ^{x}}{x ^{2}} + \frac{c _{1}}{x ^{2}}

2 e^{- 3 x}

(y + 1) d x - x d y = 0

\frac{d x}{d t} = \frac{1}{( x + t + 1 )}

(- \frac{1}{5}, \frac{1}{3}), (\frac{4}{5}, - \frac{5}{3})

\frac{\partial}{\partial y} (4 x ln (x y))

What is the solution for (e^x-2xy)dx-x^2dy=0 ?
The solution for (e^x-2xy)dx-x^2dy=0 is y=(e^x)/(x^2)+(c_{1})/(x^2)