What is the d/(dt)(e^t+e^{-t}) ?

The d/(dt)(e^t+e^{-t}) is e^t-e^{-t}

What is the first d/(dt)(e^t+e^{-t}) ?

The first d/(dt)(e^t+e^{-t}) is e^t-e^{-t}

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\frac{d}{d t} (e^{t} + e^{- t})

e^{t} - e^{- t}

Solution steps

\frac{d}{d t} (e^{t} + e^{- t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (e^{t}) + \frac{d}{d t} (e^{- t})

\frac{d}{d t} (e^{t}) = e^{t}

\frac{d}{d t} (e^{- t}) = - e^{- t}

= e^{t} - e^{- t}

f (x) = \frac{1}{11 x}

x \to 3 lim (\frac{x + 4}{x - 2})

\int (2 cos (x) - 3 sec (x) tan (x)) d x

\frac{d}{d x} ((\frac{sin ( x )}{1 + cos ( x )})^{2})

f (x) = x^{2} - 4 x

What is the d/(dt)(e^t+e^{-t}) ?
The d/(dt)(e^t+e^{-t}) is e^t-e^{-t}
What is the first d/(dt)(e^t+e^{-t}) ?
The first d/(dt)(e^t+e^{-t}) is e^t-e^{-t}