What is area f(x)=x^3-2x^2,g(x)=x^2-2x ?

The answer to area f(x)=x^3-2x^2,g(x)=x^2-2x is 1/2

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area f(x)=x^3-2x^2,g(x)=x^2-2x

area

f (x) = x^{3} - 2 x^{2}, g (x) = x^{2} - 2 x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - 2 x^{2} - (x^{2} - 2 x) d x

Solve

\int_{0}^{2} x^{3} - 2 x^{2} - (x^{2} - 2 x) d x : \frac{1}{2}

The area is:

= \frac{1}{2}

\frac{\partial}{\partial x} (2 x^{2} + 1)

x \to 6 lim (\frac{5}{6} + 9 (- \frac{2}{3}))

\frac{d}{d x} (ln (x + 7 + x^{2}))

k = 1 \sum \infty \frac{1}{4 k ^{2} - 1}

x \to 0 + lim ((x)^{x})

What is area f(x)=x^3-2x^2,g(x)=x^2-2x ?
The answer to area f(x)=x^3-2x^2,g(x)=x^2-2x is 1/2