What is the integral from 0 to 0.6 of 3000x ?

The integral from 0 to 0.6 of 3000x is 540

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integral from 0 to 0.6 of 3000x

\int_{0}^{0.6} 3000 x d x

540

Solution steps

\int_{0}^{0.6} 3000 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3000 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 3000 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 3000 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 3000 \cdot 0.18

Simplify

= 540

\int \frac{1}{( x + 2 ) ^{2}} d x

\int \frac{1}{( x + 1 ) ( x + 2 ) ^{2}} d x

\frac{d}{d x} (ln (6 x^{3} + 3 x^{2} - 2 x))

f (x) = x + 2, at (x = 4)

\int 2 y e^{y^{2}} d y

What is the integral from 0 to 0.6 of 3000x ?
The integral from 0 to 0.6 of 3000x is 540