What is the derivative of f(x)=sqrt(64-x^2) ?

The derivative of f(x)=sqrt(64-x^2) is -x/(sqrt(64-x^2))

What is the first derivative of f(x)=sqrt(64-x^2) ?

The first derivative of f(x)=sqrt(64-x^2) is -x/(sqrt(64-x^2))

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derivative of

f (x) = 64 - x^{2}

- \frac{x}{64 - x ^{2}}

Solution steps

\frac{d}{d x} (64 - x^{2})

Apply the chain rule:

\frac{1}{2 64 - x ^{2}} \frac{d}{d x} (64 - x^{2})

= \frac{1}{2 64 - x ^{2}} \frac{d}{d x} (64 - x^{2})

\frac{d}{d x} (64 - x^{2}) = - 2 x

= \frac{1}{2 64 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 64 - x ^{2}} (- 2 x) : - \frac{x}{64 - x ^{2}}

= - \frac{x}{64 - x ^{2}}

\frac{\partial}{\partial x} (x y cos (5 yz))

\int (x e^{x^{2}}) d x

\frac{d}{d x} (ln (x^{2} + 12))

csc (x), at x = \frac{π}{6}

x cos (\frac{π x}{2})

What is the derivative of f(x)=sqrt(64-x^2) ?
The derivative of f(x)=sqrt(64-x^2) is -x/(sqrt(64-x^2))
What is the first derivative of f(x)=sqrt(64-x^2) ?
The first derivative of f(x)=sqrt(64-x^2) is -x/(sqrt(64-x^2))