What is the derivative of 3x^2-4x+2 ?

The derivative of 3x^2-4x+2 is 6x-4

What is the first derivative of 3x^2-4x+2 ?

The first derivative of 3x^2-4x+2 is 6x-4

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\frac{d}{d x} (3 x^{2} - 4 x + 2)

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 6 x - 4 + 0

Simplify

= 6 x - 4

y = x^{2} - 3 x + 3, (4, 7)

\frac{d ^{2}}{d x ^{2}} (4 x + 1)

\int 2 x + 5 e^{x} d x

\frac{d}{d x} (8 x - 1)

y^{^{''}} + 9 y = 0, y (0) = 5, y^{^{'}} (0) = 1

What is the derivative of 3x^2-4x+2 ?
The derivative of 3x^2-4x+2 is 6x-4
What is the first derivative of 3x^2-4x+2 ?
The first derivative of 3x^2-4x+2 is 6x-4