What is the solution for y^{''}-2y^'-36y=0 ?

The solution for y^{''}-2y^'-36y=0 is y=c_{1}e^{(1+sqrt(37))t}+c_{2}e^{(1-sqrt(37))t}

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y^{''}-2y^'-36y=0

y^{^{''}} - 2 y^{^{'}} - 36 y = 0

y = c_{1} e^{(1 + 37) t} + c_{2} e^{(1 - 37) t}

Solution steps

y^{''} (t) - 2 y^{'} (t) - 36 y = 0

Solve linear ODE:

y = c_{1} e^{(1 + 37) t} + c_{2} e^{(1 - 37) t}

y = c_{1} e^{(1 + 37) t} + c_{2} e^{(1 - 37) t}

\int \frac{x}{2 x ^{2} + x + 3} d x

y^{^{'}} = 3 y, y (0) = 2

\int_{2}^{\infty} e^{- x} d x

\frac{\partial}{\partial x} ((sin (x - y)) (- 1.1))

y = \frac{4}{3} π r^{3}

What is the solution for y^{''}-2y^'-36y=0 ?
The solution for y^{''}-2y^'-36y=0 is y=c_{1}e^{(1+sqrt(37))t}+c_{2}e^{(1-sqrt(37))t}