What is the derivative of y=-csc(x)-cos(x) ?

The derivative of y=-csc(x)-cos(x) is cot(x)csc(x)+sin(x)

What is the first derivative of y=-csc(x)-cos(x) ?

The first derivative of y=-csc(x)-cos(x) is cot(x)csc(x)+sin(x)

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derivative of

y = - csc (x) - cos (x)

cot (x) csc (x) + sin (x)

Solution steps

\frac{d}{d x} (- csc (x) - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (csc (x)) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

\frac{d}{d x} (cos (x)) = - sin (x)

= - (- cot (x) csc (x)) - (- sin (x))

Simplify

= cot (x) csc (x) + sin (x)

2 y^{^{''}} + 8 y = 0

\int_{- \infty}^{- 1} e^{2 x} d x

\int 6 x^{2} - 3 x^{3} d x

x + y = 7, x = 0, y = 0

- \frac{14}{( t + 15 ) ^{2}}

What is the derivative of y=-csc(x)-cos(x) ?
The derivative of y=-csc(x)-cos(x) is cot(x)csc(x)+sin(x)
What is the first derivative of y=-csc(x)-cos(x) ?
The first derivative of y=-csc(x)-cos(x) is cot(x)csc(x)+sin(x)