What is the slope of y=x^3-3x^2+4 ?

The slope of y=x^3-3x^2+4 is 3x^2-6x

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slope of y=x^3-3x^2+4

slope

y = x^{3} - 3 x^{2} + 4

3 x^{2} - 6 x

Solution steps

y = x^{3} - 3 x^{2} + 4

In order to find the slope of the function, take the derivative of

x^{3} - 3 x^{2} + 4

\frac{d}{d x} (x^{3} - 3 x^{2} + 4) = 3 x^{2} - 6 x

3 x^{2} - 6 x

\frac{d}{d x} (2 (6 - x^{2})^{5})

\frac{\partial}{\partial x} (sin (x) \cdot cos (y))

x \to 1 lim (x (\frac{10}{x - 1}))

\int \frac{( 2 x ^{2} - 5 x + 2 )}{( x ^{3} + x )} d x

\frac{d}{d y} (e^{- x} cos (y))