What is the d/(dy)(e^{-x}cos(y)) ?

The d/(dy)(e^{-x}cos(y)) is -e^{-x}sin(y)

What is the first d/(dy)(e^{-x}cos(y)) ?

The first d/(dy)(e^{-x}cos(y)) is -e^{-x}sin(y)

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\frac{d}{d y} (e^{- x} cos (y))

- e^{- x} sin (y)

Solution steps

\frac{d}{d y} (e^{- x} cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- x} \frac{d}{d y} (cos (y))

Apply the common derivative:

\frac{d}{d y} (cos (y)) = - sin (y)

= e^{- x} (- sin (y))

Simplify

= - e^{- x} sin (y)

x \to 6 + lim (ln (7 - x))

y^{^{'}} = 10 - y

\int \frac{1}{4 + y ^{2}} d y

\frac{d}{d x} (\frac{x ^{2} + 4 x + 3}{x ^{2} + x})

\frac{d}{d x} (2 sec (3 x))

What is the d/(dy)(e^{-x}cos(y)) ?
The d/(dy)(e^{-x}cos(y)) is -e^{-x}sin(y)
What is the first d/(dy)(e^{-x}cos(y)) ?
The first d/(dy)(e^{-x}cos(y)) is -e^{-x}sin(y)