What is the derivative of 2sec(3x) ?

The derivative of 2sec(3x) is 6sec(3x)tan(3x)

What is the first derivative of 2sec(3x) ?

The first derivative of 2sec(3x) is 6sec(3x)tan(3x)

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\frac{d}{d x} (2 sec (3 x))

6 sec (3 x) tan (3 x)

Solution steps

\frac{d}{d x} (2 sec (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec (3 x))

Apply the chain rule:

sec (3 x) tan (3 x) \frac{d}{d x} (3 x)

= sec (3 x) tan (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 2 sec (3 x) tan (3 x) \cdot 3

Simplify

= 6 sec (3 x) tan (3 x)

y^{^{''}} + 9 x = - sin (3 x)

\frac{d}{d x} (\frac{1}{16} x^{4} + \frac{1}{2 x ^{2}})

x \to 3 lim (2 x + 3)

\frac{d}{d x} (r (x) \cdot cos (x))

n = 0 \sum \infty (- \frac{1}{2})^{n - 1}

What is the derivative of 2sec(3x) ?
The derivative of 2sec(3x) is 6sec(3x)tan(3x)
What is the first derivative of 2sec(3x) ?
The first derivative of 2sec(3x) is 6sec(3x)tan(3x)