What is (\partial)/(\partial x)(7xsin(8x^2y)) ?

The answer to (\partial)/(\partial x)(7xsin(8x^2y)) is 7(sin(8x^2y)+16x^2ycos(8x^2y))

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(\partial)/(\partial x)(7xsin(8x^2y))

\frac{\partial}{\partial x} (7 x sin (8 x^{2} y))

7 (sin (8 x^{2} y) + 16 x^{2} y cos (8 x^{2} y))

Solution steps

\frac{\partial}{\partial x} (7 x sin (8 x^{2} y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (x sin (8 x^{2} y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (8 x^{2} y)

= 7 (\frac{\partial}{\partial x} (x) sin (8 x^{2} y) + \frac{\partial}{\partial x} (sin (8 x^{2} y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (sin (8 x^{2} y)) = cos (8 x^{2} y) \cdot 16 y x

= 7 (1 \cdot sin (8 x^{2} y) + cos (8 x^{2} y) \cdot 16 y xx)

Simplify

7 (1 \cdot sin (8 x^{2} y) + cos (8 x^{2} y) \cdot 16 y xx) : 7 (sin (8 x^{2} y) + 16 x^{2} y cos (8 x^{2} y))

= 7 (sin (8 x^{2} y) + 16 x^{2} y cos (8 x^{2} y))

\frac{\partial}{\partial x} ((\frac{x ^{2} + 2}{x ^{2} - 2})^{3})

\int \frac{1}{( 81 + x ^{2} ) ^{\frac{3}{2}}} d x

x \to 0 lim (1 - cos (4 x))

1000 y^{^{''}} - 3 y^{^{'}} + 17 y = 0

\frac{d ^{6}}{d x ^{6}} ((2 x + 5)^{7})

What is (\partial)/(\partial x)(7xsin(8x^2y)) ?
The answer to (\partial)/(\partial x)(7xsin(8x^2y)) is 7(sin(8x^2y)+16x^2ycos(8x^2y))