What is the limit as x approaches 0 of 1-cos(4x) ?

The limit as x approaches 0 of 1-cos(4x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1-cos(4x)

x \to 0 lim (1 - cos (4 x))

0

Solution steps

x \to 0 lim (1 - cos (4 x))

Plug in the value

x = 0

= 1 - cos (4 \cdot 0)

Simplify

1 - cos (4 \cdot 0) : 0

= 0

1000 y^{^{''}} - 3 y^{^{'}} + 17 y = 0

\frac{d ^{6}}{d x ^{6}} ((2 x + 5)^{7})

\frac{\partial ^{2}}{\partial x ^{2}} (x^{3} + 3 x y^{2})

\frac{1}{( s - 3 ) ^{3}}

\frac{d v}{d t} = - k t v^{2}

What is the limit as x approaches 0 of 1-cos(4x) ?
The limit as x approaches 0 of 1-cos(4x) is 0