What is the derivative of 2sin(x+cos(2x)) ?

The derivative of 2sin(x+cos(2x)) is 2cos(x)-sin(2x)*2

What is the first derivative of 2sin(x+cos(2x)) ?

The first derivative of 2sin(x+cos(2x)) is 2cos(x)-sin(2x)*2

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\frac{d}{d x} (2 sin (x) + cos (2 x))

2 cos (x) - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 sin (x) + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 cos (x) - sin (2 x) \cdot 2

\int 2 x (x^{2} + 12)^{4} d x

f (x) = \frac{2}{x}, at x = 4

\frac{d}{d t} (\frac{1}{t ^{4} + 1})

\int_{0}^{2} (2 - x^{2}) d x

\frac{\partial}{\partial z} (\frac{x}{z} + \frac{y}{z})

What is the derivative of 2sin(x+cos(2x)) ?
The derivative of 2sin(x+cos(2x)) is 2cos(x)-sin(2x)*2
What is the first derivative of 2sin(x+cos(2x)) ?
The first derivative of 2sin(x+cos(2x)) is 2cos(x)-sin(2x)*2