What is (\partial)/(\partial y)(3x^2-2xy-y) ?

The answer to (\partial)/(\partial y)(3x^2-2xy-y) is -2x-1

Popular >

(\partial)/(\partial y)(3x^2-2xy-y)

\frac{\partial}{\partial y} (3 x^{2} - 2 x y - y)

- 2 x - 1

Solution steps

\frac{\partial}{\partial y} (3 x^{2} - 2 x y - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (2 x y) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (y) = 1

= 0 - 2 x - 1

Simplify

= - 2 x - 1

y = \frac{8}{sin ( x )} + \frac{1}{cot ( x )}

x \to 0 lim (\frac{5}{1 + e ^{\frac{1}{x}}})

\frac{\partial}{\partial x} (48 x^{5} y^{7} - 35 x^{4} y^{6})

f (x) = \frac{6}{( 1 + e ^{- x} ) , at ( 0 , 3 )}

\int \frac{x + 4}{x ^{2} + 11 x + 18} d x

What is (\partial)/(\partial y)(3x^2-2xy-y) ?
The answer to (\partial)/(\partial y)(3x^2-2xy-y) is -2x-1