What is the solution for (dy)/(dx)=(y^3)/(3x-2),y(1)=-1 ?

The solution for (dy)/(dx)=(y^3)/(3x-2),y(1)=-1 is y=-sqrt(-3/(2ln(-2+3x)-3))

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(dy)/(dx)=(y^3)/(3x-2),y(1)=-1

\frac{d y}{d x} = \frac{y ^{3}}{3 x - 2}, y (1) = - 1

y = - - \frac{3}{2 ln ( - 2 + 3 x ) - 3}

Solution steps

\frac{d y}{d x} = \frac{y ^{3}}{3 x - 2}

Solve separable ODE:

y = - - \frac{3}{2 ln ( - 2 + 3 x ) - 3}

y = - - \frac{3}{2 ln ( - 2 + 3 x ) - 3}

\int_{- \infty}^{5} \frac{1}{x ^{2} + 1} d x

\int 1 + cos (θ) d θ

f (x) = - 7 x^{4} + 11 x^{2} - 4, at x = 1

\int \frac{1}{x ^{2} + 4 x - 1} d x

What is the solution for (dy)/(dx)=(y^3)/(3x-2),y(1)=-1 ?
The solution for (dy)/(dx)=(y^3)/(3x-2),y(1)=-1 is y=-sqrt(-3/(2ln(-2+3x)-3))