What is the tangent of f(x)=-5cos(x),\at x=-pi/2 ?

The tangent of f(x)=-5cos(x),\at x=-pi/2 is y=-5x-(5pi)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=-5cos(x),\at x=-pi/2

tangent of

f (x) = - 5 cos (x), at x = - \frac{π}{2}

y = - 5 x - \frac{5 π}{2}

Solution steps

Find the tangent point:

(- \frac{π}{2}, 0)

Find the slope of

f (x) = - 5 cos (x) : \frac{df ( x )}{d x} = 5 sin (x)

Compute the slope of

f (x) = - 5 cos (x)

x = - \frac{π}{2} : m = - 5

Find the line with slope m=

- 5

and passing through

(- \frac{π}{2}, 0) : y = - 5 x - \frac{5 π}{2}

y = - 5 x - \frac{5 π}{2}

\frac{d}{d x} (20 (1 + e^{10 - x})^{- 1})

\frac{3}{x}

\frac{d N}{d t} + N = Nt e^{t + 6}

\frac{d}{d x} (\frac{x - 6}{x + 6})

\int \frac{x ^{3}}{a} - \frac{a}{x ^{2}} d x

What is the tangent of f(x)=-5cos(x),\at x=-pi/2 ?
The tangent of f(x)=-5cos(x),\at x=-pi/2 is y=-5x-(5pi)/2