What is the derivative of (sqrt(x)-6/(sqrt(x)+6)) ?

The derivative of (sqrt(x)-6/(sqrt(x)+6)) is 6/(sqrt(x)(\sqrt{x)+6)^2}

What is the first derivative of (sqrt(x)-6/(sqrt(x)+6)) ?

The first derivative of (sqrt(x)-6/(sqrt(x)+6)) is 6/(sqrt(x)(\sqrt{x)+6)^2}

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\frac{d}{d x} (\frac{x - 6}{x + 6})

\frac{6}{x ( x + 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 6}{x + 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 6 ) ( x + 6 ) - \frac{d}{d x} ( x + 6 ) ( x - 6 )}{( x + 6 ) ^{2}}

\frac{d}{d x} (x - 6) = \frac{1}{2 x}

\frac{d}{d x} (x + 6) = \frac{1}{2 x}

= \frac{\frac{1}{2 x} ( x + 6 ) - \frac{1}{2 x} ( x - 6 )}{( x + 6 ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( x + 6 ) - \frac{1}{2 x} ( x - 6 )}{( x + 6 ) ^{2}} : \frac{6}{x ( x + 6 ) ^{2}}

= \frac{6}{x ( x + 6 ) ^{2}}

\int \frac{x ^{3}}{a} - \frac{a}{x ^{2}} d x

y = e^{x}, y = e^{2 x}, x = 0, x = ln (4)

\frac{\partial}{\partial y} (y^{x} - ln (x^{3} y + 6 x))

x \to - 4 + lim (\frac{- 6 x}{x + 4})

\frac{\partial}{\partial x} (arctan (\frac{1}{x}))

What is the derivative of (sqrt(x)-6/(sqrt(x)+6)) ?
The derivative of (sqrt(x)-6/(sqrt(x)+6)) is 6/(sqrt(x)(\sqrt{x)+6)^2}
What is the first derivative of (sqrt(x)-6/(sqrt(x)+6)) ?
The first derivative of (sqrt(x)-6/(sqrt(x)+6)) is 6/(sqrt(x)(\sqrt{x)+6)^2}