What is (\partial)/(\partial t)(y-e^t) ?

The answer to (\partial)/(\partial t)(y-e^t) is -e^t

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(\partial)/(\partial t)(y-e^t)

\frac{\partial}{\partial t} (y - e^{t})

- e^{t}

Solution steps

\frac{\partial}{\partial t} (y - e^{t})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (y) - \frac{\partial}{\partial t} (e^{t})

\frac{\partial}{\partial t} (y) = 0

\frac{\partial}{\partial t} (e^{t}) = e^{t}

= 0 - e^{t}

Simplify

= - e^{t}

\frac{d}{d x} ((2 cos (2 x) + sin (3 x))^{2})

e^{X}

\int y^{2} x d y

x y y^{^{'}} = 4 x^{2} + y^{2}

- 3 x^{\frac{2}{3}}

What is (\partial)/(\partial t)(y-e^t) ?
The answer to (\partial)/(\partial t)(y-e^t) is -e^t