What is taylor 2e^x ?

The answer to taylor 2e^x is 2+2x+x^2+1/3 x^3+1/12 x^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor 2e^x

taylor

2 e^{x}

2 + 2 x + x^{2} + \frac{1}{3} x^{3} + \frac{1}{12} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 2 + \frac{\frac{d}{d x} ( 2 e ^{x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 2 e ^{x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 2 e ^{x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 2 + \frac{2}{1 !} x + \frac{2}{2 !} x^{2} + \frac{2}{3 !} x^{3} + \frac{2}{4 !} x^{4} + \dots

Refine

= 2 + 2 x + x^{2} + \frac{1}{3} x^{3} + \frac{1}{12} x^{4} + \dots

\int_{0}^{π} cos^{6} (θ) d θ

\frac{d}{d x} (- \frac{1}{7})

f (x) = \frac{2 e ^{6 x - 5}}{3}

\int \frac{5}{x - 6} d x

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 t}

What is taylor 2e^x ?
The answer to taylor 2e^x is 2+2x+x^2+1/3 x^3+1/12 x^4+\ldots