What is (\partial)/(\partial x)(3y^2e^x-4x) ?

The answer to (\partial)/(\partial x)(3y^2e^x-4x) is 3y^2e^x-4

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(\partial)/(\partial x)(3y^2e^x-4x)

\frac{\partial}{\partial x} (3 y^{2} e^{x} - 4 x)

3 y^{2} e^{x} - 4

Solution steps

\frac{\partial}{\partial x} (3 y^{2} e^{x} - 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y^{2} e^{x}) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (3 y^{2} e^{x}) = 3 y^{2} e^{x}

\frac{\partial}{\partial x} (4 x) = 4

= 3 y^{2} e^{x} - 4

\frac{\partial}{\partial x} (x^{2} yz)

\int \frac{x y}{x ^{2} + y ^{2} + 1} d x

\frac{d}{d x} (3 x^{4} + (2 x - 1)^{2})

\int_{1}^{4} \frac{1}{4 - x} d x

\int \frac{3 x}{( x ^{2} + 1 ) ^{2}} d x

What is (\partial)/(\partial x)(3y^2e^x-4x) ?
The answer to (\partial)/(\partial x)(3y^2e^x-4x) is 3y^2e^x-4