What is the derivative of 3x^4+(2x-1^2) ?

The derivative of 3x^4+(2x-1^2) is 12x^3+4(2x-1)

What is the first derivative of 3x^4+(2x-1^2) ?

The first derivative of 3x^4+(2x-1^2) is 12x^3+4(2x-1)

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\frac{d}{d x} (3 x^{4} + (2 x - 1)^{2})

12 x^{3} + 4 (2 x - 1)

Solution steps

\frac{d}{d x} (3 x^{4} + (2 x - 1)^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} ((2 x - 1)^{2})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} ((2 x - 1)^{2}) = 4 (2 x - 1)

= 12 x^{3} + 4 (2 x - 1)

\int_{1}^{4} \frac{1}{4 - x} d x

\int \frac{3 x}{( x ^{2} + 1 ) ^{2}} d x

\int \frac{2 ^{x}}{ln ( 2 )} x d x

\frac{d y}{d x} = \frac{( y ^{2} + x y + x ^{2} )}{x ^{2}}

What is the derivative of 3x^4+(2x-1^2) ?
The derivative of 3x^4+(2x-1^2) is 12x^3+4(2x-1)
What is the first derivative of 3x^4+(2x-1^2) ?
The first derivative of 3x^4+(2x-1^2) is 12x^3+4(2x-1)