What is the derivative of f(x)=\sqrt[9]{x} ?

The derivative of f(x)=\sqrt[9]{x} is 1/(9x^{8/9)}

What is the first derivative of f(x)=\sqrt[9]{x} ?

The first derivative of f(x)=\sqrt[9]{x} is 1/(9x^{8/9)}

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derivative of

\frac{1}{9 x ^{\frac{8}{9}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{9}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{9} x^{\frac{1}{9} - 1}

Simplify

\frac{1}{9} x^{\frac{1}{9} - 1} : \frac{1}{9 x ^{\frac{8}{9}}}

= \frac{1}{9 x ^{\frac{8}{9}}}

\int_{0}^{2} 2 d x

f (x) = (x + 2) (e^{- x})

\int 3 x cos (9 x) d x

f (x) = x^{3} - 2 x + 1

800 x^{2} - 0.3 x

What is the derivative of f(x)=\sqrt[9]{x} ?
The derivative of f(x)=\sqrt[9]{x} is 1/(9x^{8/9)}
What is the first derivative of f(x)=\sqrt[9]{x} ?
The first derivative of f(x)=\sqrt[9]{x} is 1/(9x^{8/9)}