What is the tangent of f(x)=x^3-2x+1 ?

The tangent of f(x)=x^3-2x+1 is y=(3a_{0}^2-2)x-2a_{0}^3+1

Popular >

tangent of f(x)=x^3-2x+1

tangent of

f (x) = x^{3} - 2 x + 1

y = (3 a_{0}^{2} - 2) x - 2 a_{0}^{3} + 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{3} - 2 a_{0} + 1)

Find the slope of

f (x) = x^{3} - 2 x + 1 : \frac{df ( x )}{d x} = 3 x^{2} - 2

Compute the slope of

f (x) = x^{3} - 2 x + 1

x = a_{0} : m = 3 a_{0}^{2} - 2

Find the line with slope m=

3 a_{0}^{2} - 2

and passing through

(a_{0}, a_{0}^{3} - 2 a_{0} + 1) : y = (3 a_{0}^{2} - 2) x - 2 a_{0}^{3} + 1

y = (3 a_{0}^{2} - 2) x - 2 a_{0}^{3} + 1

800 x^{2} - 0.3 x

\frac{d}{d x} (lo g_{3} (sec (x)))

f (x) = \frac{x}{1 + x ^{2}}, (0, 0)

\frac{d}{d x} (\frac{3 - sec ( x )}{tan ( x )})

\frac{\partial}{\partial y} (ln (x - 2 y + 3 z))

What is the tangent of f(x)=x^3-2x+1 ?
The tangent of f(x)=x^3-2x+1 is y=(3a_{0}^2-2)x-2a_{0}^3+1