What is the integral from 1 to 7 of 6/(x^2) ?

The integral from 1 to 7 of 6/(x^2) is 36/7

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integral from 1 to 7 of 6/(x^2)

\int_{1}^{7} \frac{6}{x ^{2}} d x

\frac{36}{7}

Decimal Notation

5.14285 \dots

Solution steps

\int_{1}^{7} \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{7} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{7}

= 6 [- \frac{1}{x}]_{1}^{7}

Compute the boundaries:

\frac{6}{7}

= 6 \cdot \frac{6}{7}

Simplify

= \frac{36}{7}

t^{2} y^{^{''}} - 2 y = 6 t^{2} - 1

\frac{d}{d y} (y (2 x + y^{3}))

\int 2 sin (x) - tan (x) d x

\frac{\partial}{\partial x} (sin (π (4 x - y)))

\frac{d p}{2 ( p + 3 )} = \frac{d v}{- v}

What is the integral from 1 to 7 of 6/(x^2) ?
The integral from 1 to 7 of 6/(x^2) is 36/7