What is (\partial)/(\partial x)(sin(pi(4x-y))) ?

The answer to (\partial)/(\partial x)(sin(pi(4x-y))) is cos(pi(4x-y))*4pi

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(\partial)/(\partial x)(sin(pi(4x-y)))

\frac{\partial}{\partial x} (sin (π (4 x - y)))

cos (π (4 x - y)) \cdot 4 π

Solution steps

\frac{\partial}{\partial x} (sin (π (4 x - y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (4 x - y)) \frac{\partial}{\partial x} (π (4 x - y))

= cos (π (4 x - y)) \frac{\partial}{\partial x} (π (4 x - y))

\frac{\partial}{\partial x} (π (4 x - y)) = 4 π

= cos (π (4 x - y)) \cdot 4 π

\frac{d p}{2 ( p + 3 )} = \frac{d v}{- v}

x \to 0 + lim (x sin (x))

\int x^{2} x e^{x^{2}} d x

y^{3} - (14 x + 2) + 3 x y^{2} y^{^{'}} = 0

What is (\partial)/(\partial x)(sin(pi(4x-y))) ?
The answer to (\partial)/(\partial x)(sin(pi(4x-y))) is cos(pi(4x-y))*4pi