What is the derivative of \sqrt[5]{x^4}-5/x ?

The derivative of \sqrt[5]{x^4}-5/x is (4x^3)/(5(x^4)^{4/5)}+5/(x^2)

What is the first derivative of \sqrt[5]{x^4}-5/x ?

The first derivative of \sqrt[5]{x^4}-5/x is (4x^3)/(5(x^4)^{4/5)}+5/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} + \frac{5}{x ^{2}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{5}{x}) = - \frac{5}{x ^{2}}

= \frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} - (- \frac{5}{x ^{2}})

Simplify

= \frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} + \frac{5}{x ^{2}}

\frac{d}{d x} (7 sin (2 x) + 3 tan (x - 1))

\int \frac{1}{( x ^{2} - 2 x + 5 ) ^{\frac{3}{2}}} d x

y^{^{'''}} - 5 y^{^{''}} - 22 y^{^{'}} + 56 y = 0

y = (x^{3} - 2) (x^{2} - 3 x + 1), (2, - 6)

\frac{d x}{d t} = 7 x

What is the derivative of \sqrt[5]{x^4}-5/x ?
The derivative of \sqrt[5]{x^4}-5/x is (4x^3)/(5(x^4)^{4/5)}+5/(x^2)
What is the first derivative of \sqrt[5]{x^4}-5/x ?
The first derivative of \sqrt[5]{x^4}-5/x is (4x^3)/(5(x^4)^{4/5)}+5/(x^2)