What is the first derivative of x^2+i ?

The first derivative of x^2+i is 2x

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derivative of x^2+i

\frac{d}{d x} (x^{2} + i)

2 x

Solution steps

\frac{d}{d x} (x^{2} + i)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d i}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d i}{d x} = 0

= 2 x + 0

Simplify

= 2 x

\int (1 + ln (x) + \frac{y}{x}) d x

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\frac{1}{( z - 1 )} \cdot \frac{1}{e ^{z + 1}}

\int \frac{x + 4}{x ^{2} + 25} d x

\frac{d}{d x} (2 0^{x})