What is the solution for (dy)/(dx)+6x^2y=-3x^2 ?

The solution for (dy)/(dx)+6x^2y=-3x^2 is y=(e^{-2x^3+c_{1}})/2-1/2

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(dy)/(dx)+6x^2y=-3x^2

\frac{d y}{d x} + 6 x^{2} y = - 3 x^{2}

y = \frac{e ^{- 2 x^{3} + c_{1}}}{2} - \frac{1}{2}

Solution steps

\frac{d y}{d x} + 6 x^{2} y = - 3 x^{2}

Solve separable ODE:

y = \frac{e ^{- 2 x^{3} + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{- 2 x^{3} + c_{1}}}{2} - \frac{1}{2}

(2 π r^{2}) + (\frac{80}{r})

\int_{0}^{6} \frac{3 t}{( t - 7 ) ^{2}} d t

\frac{d}{d x} (\frac{4 x ^{2} + 7 x ^{5}}{x})

x \to 0 lim (\frac{2}{2 x})

\frac{d v}{d t} = 9.8 - 1.2 v

What is the solution for (dy)/(dx)+6x^2y=-3x^2 ?
The solution for (dy)/(dx)+6x^2y=-3x^2 is y=(e^{-2x^3+c_{1}})/2-1/2