What is (\partial)/(\partial x)(-ycos(-3x)) ?

The answer to (\partial)/(\partial x)(-ycos(-3x)) is 3ysin(3x)

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(\partial)/(\partial x)(-ycos(-3x))

\frac{\partial}{\partial x} (- y cos (- 3 x))

3 y sin (3 x)

Solution steps

\frac{\partial}{\partial x} (- y cos (- 3 x))

Simplify

- y cos (- 3 x) : - y cos (3 x)

= \frac{\partial}{\partial x} (- y cos (3 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - y (- sin (3 x) \cdot 3)

Simplify

= 3 y sin (3 x)

n = 2 \sum \infty \frac{( n - 1 )}{n}

- x^{4} + 2 x^{3} + 4 x^{2}

f (x) = 3 x^{2} + 2

\int 2^{l n (x)} d x

f (x) = x - 2

What is (\partial)/(\partial x)(-ycos(-3x)) ?
The answer to (\partial)/(\partial x)(-ycos(-3x)) is 3ysin(3x)