What is the derivative of t^5-1/(\sqrt[4]{t^7)} ?

The derivative of t^5-1/(\sqrt[4]{t^7)} is 5t^4+(7t^6)/(4(t^7)^{5/4)}

What is the first derivative of t^5-1/(\sqrt[4]{t^7)} ?

The first derivative of t^5-1/(\sqrt[4]{t^7)} is 5t^4+(7t^6)/(4(t^7)^{5/4)}

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derivative of

5 t^{4} + \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (t^{5}) = 5 t^{4}

= 5 t^{4} - (- \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}})

Simplify

= 5 t^{4} + \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}}

\frac{d}{d x} (\frac{x ^{3}}{( 1 - x ) ^{2}})

\frac{d}{d x} (x^{2} + y^{2} - z)

\int x^{r} d x

\frac{x ^{2} - 6 x + 12}{x - 4}

y^{^{'}} + y = e^{- x} x

What is the derivative of t^5-1/(\sqrt[4]{t^7)} ?
The derivative of t^5-1/(\sqrt[4]{t^7)} is 5t^4+(7t^6)/(4(t^7)^{5/4)}
What is the first derivative of t^5-1/(\sqrt[4]{t^7)} ?
The first derivative of t^5-1/(\sqrt[4]{t^7)} is 5t^4+(7t^6)/(4(t^7)^{5/4)}