What is the derivative of (x^2-6x+12)/(x-4) ?

The derivative of (x^2-6x+12)/(x-4) is (x^2-8x+12)/((x-4)^2)

What is the first derivative of (x^2-6x+12)/(x-4) ?

The first derivative of (x^2-6x+12)/(x-4) is (x^2-8x+12)/((x-4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{x ^{2} - 6 x + 12}{x - 4}

\frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 6 x + 12}{x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 6 x + 12 ) ( x - 4 ) - \frac{d}{d x} ( x - 4 ) ( x ^{2} - 6 x + 12 )}{( x - 4 ) ^{2}}

\frac{d}{d x} (x^{2} - 6 x + 12) = 2 x - 6

\frac{d}{d x} (x - 4) = 1

= \frac{( 2 x - 6 ) ( x - 4 ) - 1 \cdot ( x ^{2} - 6 x + 12 )}{( x - 4 ) ^{2}}

Simplify

\frac{( 2 x - 6 ) ( x - 4 ) - 1 \cdot ( x ^{2} - 6 x + 12 )}{( x - 4 ) ^{2}} : \frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}}

= \frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}}

y^{^{'}} + y = e^{- x} x

\int \frac{2 x ^{2} + 7 x + 2}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d x} (3 x^{\frac{2}{3}} - x)

\frac{d}{d x} ((2 x + 1)^{- 1})

\int \frac{arcsin ( x )}{x} d x

What is the derivative of (x^2-6x+12)/(x-4) ?
The derivative of (x^2-6x+12)/(x-4) is (x^2-8x+12)/((x-4)^2)
What is the first derivative of (x^2-6x+12)/(x-4) ?
The first derivative of (x^2-6x+12)/(x-4) is (x^2-8x+12)/((x-4)^2)