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Popular >

integral from 0 to 1 of (1+4xy)

Solution

\int_{0}^{1} (1 + 4 x y) d x

Solution

1 + 2 y

Solution steps

\int_{0}^{1} 1 + 4 x y d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x + \int_{0}^{1} 4 y x d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} 4 y x d x = 2 y

= 1 + 2 y

Popular Examples

tangent of y=3+4x^2-2x^3,(2,3)tangent of

y = 3 + 4 x^{2} - 2 x^{3}, (2, 3)

derivative of (4+csc(x)/(8-csc(x)))

\frac{d}{d x} (\frac{4 + csc ( x )}{8 - csc ( x )})

integral of 4x^3ln(x)

\int 4 x^{3} ln (x) d x

derivative of cx+ln(cos(x))

\frac{d}{d x} (c x + ln (cos (x)))

y^{^{'}} + r y^{^{''}} = 0

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (1+4xy) ?
The integral from 0 to 1 of (1+4xy) is 1+2y