What is the d/(dt)(1+4sqrt(t)) ?

The d/(dt)(1+4sqrt(t)) is 2/(sqrt(t))

What is the first d/(dt)(1+4sqrt(t)) ?

The first d/(dt)(1+4sqrt(t)) is 2/(sqrt(t))

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\frac{d}{d t} (1 + 4 t)

\frac{2}{t}

Solution steps

\frac{d}{d t} (1 + 4 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (4 t)

\frac{d}{d t} (1) = 0

\frac{d}{d t} (4 t) = \frac{2}{t}

= 0 + \frac{2}{t}

Simplify

= \frac{2}{t}

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (\frac{π}{2}) = 0, y^{^{'}} (\frac{π}{2}) = 2

x \to 0 lim ((ln (x)) - \frac{1}{x})

x \to - 2 lim (- (x^{2} - x + 1))

\int_{1}^{2} x^{10} d x

y = \frac{5}{x ^{2}}

What is the d/(dt)(1+4sqrt(t)) ?
The d/(dt)(1+4sqrt(t)) is 2/(sqrt(t))
What is the first d/(dt)(1+4sqrt(t)) ?
The first d/(dt)(1+4sqrt(t)) is 2/(sqrt(t))