What is the limit as x approaches 0 of (ln(x))-1/x ?

The limit as x approaches 0 of (ln(x))-1/x is Does not exist

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limit as x approaches 0 of (ln(x))-1/x

x \to 0 lim ((ln (x)) - \frac{1}{x})

Does not exist

Solution steps

x \to 0 lim (ln (x) - \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (x) - \frac{1}{x}) = - \infty

x \to 0 - lim (ln (x) - \frac{1}{x}) =

Does not exist

= Does not exist

x \to - 2 lim (- (x^{2} - x + 1))

\int_{1}^{2} x^{10} d x

y = \frac{5}{x ^{2}}

ln (e^{7 x - 2})

y^{^{''}} + 4 y^{^{'}} + 10 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the limit as x approaches 0 of (ln(x))-1/x ?
The limit as x approaches 0 of (ln(x))-1/x is Does not exist