What is (\partial)/(\partial x)(y/x-1) ?

The answer to (\partial)/(\partial x)(y/x-1) is -y/(x^2)

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(\partial)/(\partial x)(y/x-1)

\frac{\partial}{\partial x} (\frac{y}{x} - 1)

- \frac{y}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y}{x} - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{y}{x}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (\frac{y}{x}) = - \frac{y}{x ^{2}}

\frac{\partial}{\partial x} (1) = 0

= - \frac{y}{x ^{2}} - 0

Simplify

= - \frac{y}{x ^{2}}

f (x) = cos (\frac{x ^{2} - 25}{x - 5})

x \to 0 lim (\frac{2 x + x ^{2}}{x})

\int 4 x^{3} n xx d x

\frac{d y}{d x} = \frac{y ^{2} - x ^{2}}{2 x y}

\frac{s ^{4} + 1}{s ^{3} - s}

What is (\partial)/(\partial x)(y/x-1) ?
The answer to (\partial)/(\partial x)(y/x-1) is -y/(x^2)