What is the solution for (dy)/(dx)=(y^2-x^2)/(2xy) ?

The solution for (dy)/(dx)=(y^2-x^2)/(2xy) is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}

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(dy)/(dx)=(y^2-x^2)/(2xy)

\frac{d y}{d x} = \frac{y ^{2} - x ^{2}}{2 x y}

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{y ^{2} - x ^{2}}{2 x y}

Solve Bernoulli ODE:

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

\frac{s ^{4} + 1}{s ^{3} - s}

\int sin (8 x) cos (4 x) d x

f (x) = \frac{4 x}{x - 3}, at x = 5

(\frac{10}{9}) t^{2}

5 y^{^{''}} + y^{^{'}} = - 6 x

What is the solution for (dy)/(dx)=(y^2-x^2)/(2xy) ?
The solution for (dy)/(dx)=(y^2-x^2)/(2xy) is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}